4c^2+3c-2=0

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Solution for 4c^2+3c-2=0 equation:



4c^2+3c-2=0
a = 4; b = 3; c = -2;
Δ = b2-4ac
Δ = 32-4·4·(-2)
Δ = 41
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{41}}{2*4}=\frac{-3-\sqrt{41}}{8} $
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{41}}{2*4}=\frac{-3+\sqrt{41}}{8} $

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